2log5 10+log5 0.25= 2log5 25-3log2 64= log2(log2 16)= 已知lg2=

来源：学生作业帮编辑：搜搜做题作业网作业帮分类：数学作业时间：2024/08/10 20:59:21

2log5 10+log5 0.25= 2log5 25-3log2 64= log2(log2 16)= 已知lg2=a,lg3=b,求log3 4,log2 12

已知lg2=a,lg3=b,
log3 4=lg4/lg3=2lg2/lg3=2a/b,
log2 12=log2 (2^2×3)=2+log2 3=2+lg3/lg2=2+b/a.
前面部分意思不懂.
再问：抱歉啊，重发一下 2log5 10+log5 0.25= 2log5 25-3log2 64= log2(log2 16)=
再答： 2log5 10+log5 0.25=log5 100+log5 0.25=log5 25=2， 2log5 25-3log2 64=2log5 5^2-3log2 2^6=4-18=-14， log2(log2 16)=log(log2 2^4)=log2 4=2。

2log5(25)-3log2(64)=? (1/log2 10) + (1/log5 10) =lg2 + lg5 log2^25*log3^2倍根号2*log5^9= log的计算：log2（20）-log4（25)= log3(2)×log2（5）×log5（3）=?log2[log log2^5*log3^2倍根号2*log5^9= 我是这样做的log2(3)*log3(5)*log5(49)*log7(64)=log2(3)*log3(5)*2log 2log5^10+log5^0.25=? (Log2)的三次方+(Log5)的三次方+3*lg2*lg5=? 有关log的数学题①log2(2X+3)=0②log5(X)-1/3log5(8)=0③log2(X)+log4(X)= log2/27及 log 3=a log5=b (log3^4+log5^2)(log2^9+log2^根号3) 求值 3^2-log3(2)= log7(log5(log2(32)))=?