已知数列an前n项和为Sn,且满足a1=4,Sn+Sn+1=5/3an+1
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已知数列an前n项和为Sn,且满足a1=4,Sn+Sn+1=5/3an+1
![已知数列an前n项和为Sn,且满足a1=4,Sn+Sn+1=5/3an+1](/uploads/image/z/158537-65-7.jpg?t=%E5%B7%B2%E7%9F%A5%E6%95%B0%E5%88%97an%E5%89%8Dn%E9%A1%B9%E5%92%8C%E4%B8%BASn%2C%E4%B8%94%E6%BB%A1%E8%B6%B3a1%3D4%2CSn%2BSn%2B1%3D5%2F3an%2B1)
林永嘉,把分给我把,哈哈.
Sn+S(n+1)=(5/3)a(n+1)=(5/3)[S(n+1)-Sn]
4Sn=Sn+1
Sn+1/Sn=4
则,Sn成等比数列
S1=a1
Sn=4*4^(n-1)=4^n
你的班长大人啊聪明啊.哈哈.不要崇拜姐啊.
再给点分.
Sn+S(n+1)=(5/3)a(n+1)=(5/3)[S(n+1)-Sn]
4Sn=Sn+1
Sn+1/Sn=4
则,Sn成等比数列
S1=a1
Sn=4*4^(n-1)=4^n
你的班长大人啊聪明啊.哈哈.不要崇拜姐啊.
再给点分.
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