搜搜做题作业网求函数的极限：lim(1^n+2^n+3^n+4^n)^1/n,当n→∞时的极限.(不用夹逼准则解)
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求函数的极限：lim(1^n+2^n+3^n+4^n)^1/n,当n→∞时的极限.(不用夹逼准则解)
n→∞
lim(1^n+2^n+3^n+4^n)^(1/n)
=e^lim[(1/n)*ln(1^n+2^n+3^n+4^n)]
下面求lim[(1/n)*ln(1^n+2^n+3^n+4^n)]
=lim(1/n)*ln{(4^n)*[(1/4)^n+(2/4)^n+(3/4)^n+1]}
=lim(1/n)*{nln4+ln[1+(1/4)^n+(2/4)^n+(3/4)^n]}
这里ln[1+(1/4)^n+(2/4)^n+(3/4)^n]等价于(1/4)^n+(2/4)^n+(3/4)^n
=ln4+lim[(1/4)^n+(2/4)^n+(3/4)^n]/n
=ln4
所以最后结果为e^ln4=4
lim(1^n+2^n+3^n+4^n)^(1/n)
=e^lim[(1/n)*ln(1^n+2^n+3^n+4^n)]
下面求lim[(1/n)*ln(1^n+2^n+3^n+4^n)]
=lim(1/n)*ln{(4^n)*[(1/4)^n+(2/4)^n+(3/4)^n+1]}
=lim(1/n)*{nln4+ln[1+(1/4)^n+(2/4)^n+(3/4)^n]}
这里ln[1+(1/4)^n+(2/4)^n+(3/4)^n]等价于(1/4)^n+(2/4)^n+(3/4)^n
=ln4+lim[(1/4)^n+(2/4)^n+(3/4)^n]/n
=ln4
所以最后结果为e^ln4=4
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