如图,已知:∠BAC=∠DAE,∠ABD=∠ACE,BD=CE,求证:AD=AE
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/10 06:17:28
如图,已知:∠BAC=∠DAE,∠ABD=∠ACE,BD=CE,求证:AD=AE
![如图,已知:∠BAC=∠DAE,∠ABD=∠ACE,BD=CE,求证:AD=AE](/uploads/image/z/15552943-7-3.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%B7%B2%E7%9F%A5%3A%E2%88%A0BAC%3D%E2%88%A0DAE%2C%E2%88%A0ABD%3D%E2%88%A0ACE%2CBD%3DCE%2C%E6%B1%82%E8%AF%81%3AAD%3DAE)
证明:
∵∠BAD=∠BAC-∠CAD,∠CAE=∠DAE-∠CAD,∠BAC=∠DAE
∴∠BAD=∠CAE
∵∠ABD=∠ACE,BD=CE
∴△ABD≌△ACE (AAS)
∴AD=AE
∵∠BAD=∠BAC-∠CAD,∠CAE=∠DAE-∠CAD,∠BAC=∠DAE
∴∠BAD=∠CAE
∵∠ABD=∠ACE,BD=CE
∴△ABD≌△ACE (AAS)
∴AD=AE
如图,已知∠BAC=∠DAE ,∠ABD=∠ACE ,BD=CE 求证:AB=AC,AD=AE
如图,已知角BAC=角DAE,角ABD=角ACE BD=CE,求证,AD=AE
如图,已知∠BAC=∠DAE,AB=AC,AD=AE,你能说明BD=CE,∠ABD=∠ACE么?T0T)
如图,已知∠BAC=∠DAE,∠ABD=∠ACE,BD=CE,那么AB与AC,AD与AE有什么数量关系?
如图所示,已知∠BAC=∠DAE,∠ABD=∠ACE,BD=CE.求证:AB=AC,AD=AE
已知∠BAC=∠DAE,∠ABD=∠ACE,BD=CE,说明AB=AC,AD=AE,
已知:如图,AB=AC,AD=AE,BD=CE,求证:∠BAC=∠DAE
已知:如图,AD=AE,AB=AC,∠DAE=∠BAC.求证:BD=CE.
已知:如图6-7,AD=AE,AB=AC,∠DAE=∠BAC.求证:BD=CE.
如图已知角BAC=角DAE,角ABD=角ACE,BD=CE.问AB=AC,AD=AE成立吗
如图,已知AD=AE,BD=CE.求证:三角形ABD≌三角形ACE
如图,在△ABC和△ADE中,AB=AC,AD=AE,∠BAC=∠DAE,求证:△ABD≌△ACE.