设f(x)在[0,1]上有连续导数,且f(0)=f(1)=0,证明|∫(0,1)f(x)dx|≤1/4max(0≤x≤1
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设f(x)在[0,1]上有连续导数,且f(0)=f(1)=0,证明|∫(0,1)f(x)dx|≤1/4max(0≤x≤1)|f'(x)|
![设f(x)在[0,1]上有连续导数,且f(0)=f(1)=0,证明|∫(0,1)f(x)dx|≤1/4max(0≤x≤1](/uploads/image/z/15548474-2-4.jpg?t=%E8%AE%BEf%28x%29%E5%9C%A8%5B0%2C1%5D%E4%B8%8A%E6%9C%89%E8%BF%9E%E7%BB%AD%E5%AF%BC%E6%95%B0%2C%E4%B8%94f%280%29%3Df%281%29%3D0%2C%E8%AF%81%E6%98%8E%7C%E2%88%AB%EF%BC%880%2C1%29f%28x%29dx%7C%E2%89%A41%2F4max%280%E2%89%A4x%E2%89%A41)
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