-(-3a-2b+2c)-{-a+[4a-(a-b-c)-3a]+2c}
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-(-3a-2b+2c)-{-a+[4a-(a-b-c)-3a]+2c}
-(-3a-2b+2c)-{-a+[4a-(a-b-c)-3a]+2c}
=3a+2b-2c+a-4a+a+b+c-3a-2c
=-3a+3b-3c
=3a+2b-2c+a-4a+a+b+c-3a-2c
=-3a+3b-3c
(a-b)(b-c)(c-a)/(b-a)(a-c)2(c-b)3
5a-{-3b+[6c-2a-(a-c)]}-[9a-(7b+c)]
(a+b-c)^5(a-b-c)^2(c-a-b)^4(c+b-a)^3 计算
已知A=3a-2b+c,B=a+4b-2c,C=a-3c,求:A-(B+C).
化简(2a-b-c)/(a+b)(a-c)+(2b-c-a)/(b-c)(b-a)+(2c-a-b)/(c-b)(c-a
化简:5(a-2b+c)-4(-a+b-c)+4(3a-2b)
化简|c|-2|c+b|+|c-a|-4|b+a|
3a-{2c-[6a-(c-b)+c+(a+8b-6)]}.
证明:8(a+b+c)^3-(b+c)^3-(c+a)^3-(a+b)^3=3(2a+b+c)(a+2b+c)(a+b+
(c-2b+3a)(2b+c-3a)
(a+2b+3c)(-a-3c-2b)
a、b、c互不相等,则2a-b-c/(a-b)(a-c)+2b-c-a/(b-c)(b-a)+2c-a-b/(c-a)(