2x²+6=7x
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2x²+6=7x
![2x²+6=7x](/uploads/image/z/1549880-8-0.jpg?t=2x%26sup2%3B%2B6%3D7x)
2x²+6=7x
2x^2-7x+6=0
Δ=b^2-4ac
=7^2-4x2x6
=1
x=(-b±根号Δ)/2a
x1=(7+1)/4=2
x2=(7-1)/4=3/2=1.5
2x^2-7x+6=0
Δ=b^2-4ac
=7^2-4x2x6
=1
x=(-b±根号Δ)/2a
x1=(7+1)/4=2
x2=(7-1)/4=3/2=1.5