由方程ysinx-cos(x+y)=0确定隐函数y(x),求dy|(0,π/2)
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/06/30 16:40:16
由方程ysinx-cos(x+y)=0确定隐函数y(x),求dy|(0,π/2)
![由方程ysinx-cos(x+y)=0确定隐函数y(x),求dy|(0,π/2)](/uploads/image/z/15074080-16-0.jpg?t=%E7%94%B1%E6%96%B9%E7%A8%8Bysinx-cos%28x%2By%29%3D0%E7%A1%AE%E5%AE%9A%E9%9A%90%E5%87%BD%E6%95%B0y%28x%29%2C%E6%B1%82dy%7C%280%2C%CF%80%2F2%29)
两边求导:
y'sinx+ycosx+sin(x+y)*(1+y')=0
令x=0,y=π/2:π/2+1+y'=0
y'=-(π/2+1)
dy=-(π/2+1)dx
y'sinx+ycosx+sin(x+y)*(1+y')=0
令x=0,y=π/2:π/2+1+y'=0
y'=-(π/2+1)
dy=-(π/2+1)dx
由方程ysinx-cos(x+y)=0确定隐函数y(x),求dy|(0,π/2)
求由方程ysinx-cos(xy)=0所确定的隐函数y=y(x)的导数dy/dx
ysinx-cos(x+y)=0,求 dy/dx
ysinx+cos(x-y)=0,求dy/dx|(x=π/2)
设y=y(x) 由方程ysinx=cos(x-y) 所确定,则y'(0)=
由方程cos(x+y)+e^y=x确定y和x的隐函数,求dy
已知ysinx-cos(x+y)=0,求在点(0,π)的dy/dx值
由方程x+e^(x²+y)+cos(y/x)=0确定的函数y=y(x),求dy/dx...
已知ysinx-cos(x+y)=0,求在点(0,π/2)的dy/dx值
求函数的微分或导数!1,设ysinx-cos(x-y)=0,求dy解利用一阶微分的形式的不变性求得d(ysinx)-dc
设函数y由方程ln y+x/y=0确定,求dy/dx
设函数y=y(x)由方程cos(x+y)+y=1确定,求dy/dx