已知x/2=y/3=z/5 且3x+2y-2z=4 求xyz的值
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已知x/2=y/3=z/5 且3x+2y-2z=4 求xyz的值
x/2=y/3
3x=2y
x/2=z/5
5x=2z
x=2z/5
3x=6z/5
y/3=z/5
3z=5y
z=5y/3
2z=10y/3
2y=6z/5
所以3x+2y-2z=4
3x+3x-5x=4
x=4
3x+2y-2z=4
2y+2y-10y/3=4
y=6
3x+2y-2z=4
6z/5+6z/5-2z=4
z=10
xyz=240
3x=2y
x/2=z/5
5x=2z
x=2z/5
3x=6z/5
y/3=z/5
3z=5y
z=5y/3
2z=10y/3
2y=6z/5
所以3x+2y-2z=4
3x+3x-5x=4
x=4
3x+2y-2z=4
2y+2y-10y/3=4
y=6
3x+2y-2z=4
6z/5+6z/5-2z=4
z=10
xyz=240
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