已知 x-3y=0 求(2x+y)/(x²-2xy+y²)*(x-y)
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已知 x-3y=0 求(2x+y)/(x²-2xy+y²)*(x-y)
有分……
有分……
![已知 x-3y=0 求(2x+y)/(x²-2xy+y²)*(x-y)](/uploads/image/z/14764347-27-7.jpg?t=%E5%B7%B2%E7%9F%A5+x-3y%3D0+%E6%B1%82%EF%BC%882x%2By%EF%BC%89%2F%EF%BC%88x%26%23178%3B-2xy%2By%26%23178%3B%EF%BC%89%2A%EF%BC%88x-y%EF%BC%89)
x-3y=0
x=3y
(2x+y)/(x²-2xy+y²)*(x-y)
=(2x+y)/(x-y)
=(7y)/(2y)
=7/2
x=3y
(2x+y)/(x²-2xy+y²)*(x-y)
=(2x+y)/(x-y)
=(7y)/(2y)
=7/2
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