已知x-y=2,y-z=2,x+z=14,求x²-z²的值.
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已知x-y=2,y-z=2,x+z=14,求x²-z²的值.
![已知x-y=2,y-z=2,x+z=14,求x²-z²的值.](/uploads/image/z/14753236-4-6.jpg?t=%E5%B7%B2%E7%9F%A5x-y%3D2%2Cy-z%3D2%2Cx%2Bz%3D14%2C%E6%B1%82x%26%23178%3B-z%26%23178%3B%E7%9A%84%E5%80%BC.)
x-y=2,y-z=2
x-y+y-z=2+2
x-z=4
x+z=14
x²-z²
=(x-z)(x+z)
=4*14
=56
x-y+y-z=2+2
x-z=4
x+z=14
x²-z²
=(x-z)(x+z)
=4*14
=56
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