解方程1/(x^3+3x+2)+1/(x^3+5x+6)+1/(x^3+7x+12)=1/(x+4)
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解方程1/(x^3+3x+2)+1/(x^3+5x+6)+1/(x^3+7x+12)=1/(x+4)
早上就要,
早上就要,
![解方程1/(x^3+3x+2)+1/(x^3+5x+6)+1/(x^3+7x+12)=1/(x+4)](/uploads/image/z/1459202-50-2.jpg?t=%E8%A7%A3%E6%96%B9%E7%A8%8B1%2F%28x%5E3%2B3x%2B2%29%2B1%2F%28x%5E3%2B5x%2B6%29%2B1%2F%28x%5E3%2B7x%2B12%29%3D1%2F%28x%2B4%29)
1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)=1/(x+4)
1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+1/(x+3)-1/(x+4)=1/(x+4)
1/(x+1)-1/(x+4)=1/(x+4)
1/(x+1)=2/(x+4)
2(x+1)=x+4
2x+1=x+4
2x-x=4-1
x=3
经检验,x=3是原方程的解
1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+1/(x+3)-1/(x+4)=1/(x+4)
1/(x+1)-1/(x+4)=1/(x+4)
1/(x+1)=2/(x+4)
2(x+1)=x+4
2x+1=x+4
2x-x=4-1
x=3
经检验,x=3是原方程的解
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