若lg2=m,lg3 10=1/n,则lg5 6=
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/08 10:04:00
若lg2=m,lg3 10=1/n,则lg5 6=
设x^a=y^b=z^c,且1/a+1/b=1/c,求证:z=xy
3^a=2,则log3 16-2/log18 3用a表示
设x^a=y^b=z^c,且1/a+1/b=1/c,求证:z=xy
3^a=2,则log3 16-2/log18 3用a表示
1. lg2+lg5=1;lg5=1-m
lg3=n;
log5 6=lg6/lg5=(lg2+lg3)/lg5=(m+n)/(1-m);
2. 令x^a=k;
logx k=a;logy k=b;logz k=c;
1/a+1/b=(lgx+lgy)/lgk=lgxy/lgk=1/c=lgz/lgk;
xy=z;
3. a=log3 2
log3 16-2/log18 3=4*log3 2-2*lg18/lg3
=4*log3 2-2*(lg9+lg2)/lg3
=4*log3 2-2*(2+lg3 2)
=4a-4-2a
=2a-4
lg3=n;
log5 6=lg6/lg5=(lg2+lg3)/lg5=(m+n)/(1-m);
2. 令x^a=k;
logx k=a;logy k=b;logz k=c;
1/a+1/b=(lgx+lgy)/lgk=lgxy/lgk=1/c=lgz/lgk;
xy=z;
3. a=log3 2
log3 16-2/log18 3=4*log3 2-2*lg18/lg3
=4*log3 2-2*(lg9+lg2)/lg3
=4*log3 2-2*(2+lg3 2)
=4a-4-2a
=2a-4
若lg2=m,lg3 10=1/n,则lg5 6=
请问lg2.lg3.lg5=?
lg2*lg3=?lg5/lg2=?
(lg3(lg2+lg5)/lg2lg5) *[ lg5(lg3+lg9)/lg3lg9]*lg2=(lg3+2lg3)
lg2=0.3010 lg3=0.4771 lg15 =lg3+lg5 =lg3+1-lg2 =1.7781 中lg3+
已知lg3=m,lg5=n,则10∧3m-2n为多少
2lg5/lg2*2lg2/lg3*2lg3/lg5=多少,
(2lg5·2lg2·2lg3)/(lg5·lg2·lg3)=
lg15=lg3+lg5=lg3+1-lg2,请问最后一步是怎么来的?
lg2^2+lg2*lg5+lg5=lg2(lg2+lg5)+lg5
lg2=A.lg3=B.lg5=?
设lg3=a lg2=b 求lg5(18)