ysin3x-cos(y-x)=5 y=f(x) 求dy/dx
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ysin3x-cos(y-x)=5 y=f(x) 求dy/dx
![ysin3x-cos(y-x)=5 y=f(x) 求dy/dx](/uploads/image/z/13792711-31-1.jpg?t=ysin3x-cos%28y-x%29%3D5+y%3Df%28x%29+%E6%B1%82dy%2Fdx)
两边取导数
得:[ysin3x-cos(y-x)]`=0
即:y`sin3x+3ycos3x-sin(y-x)(y`-1)=0
即:y`sin3x-y`sin(y-x)=sin(y-x)-3xcos3x
所以:y`=[sin(y-x)-3xcos3x]/[sin3x-sin(y-x)]
得:[ysin3x-cos(y-x)]`=0
即:y`sin3x+3ycos3x-sin(y-x)(y`-1)=0
即:y`sin3x-y`sin(y-x)=sin(y-x)-3xcos3x
所以:y`=[sin(y-x)-3xcos3x]/[sin3x-sin(y-x)]
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