已知x,y是实数且满足sinx*cosy=1,则cos(x+y)=
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已知x,y是实数且满足sinx*cosy=1,则cos(x+y)=
![已知x,y是实数且满足sinx*cosy=1,则cos(x+y)=](/uploads/image/z/13171157-53-7.jpg?t=%E5%B7%B2%E7%9F%A5x%2Cy%E6%98%AF%E5%AE%9E%E6%95%B0%E4%B8%94%E6%BB%A1%E8%B6%B3sinx%2Acosy%3D1%2C%E5%88%99cos%28x%2By%29%3D)
sinx*cosy=1
sinx=cosy=1或sinx=cosy=-1
cosx=siny=0
因此cos(x+y)=cosxcosy-sinxsiny=0
sinx=cosy=1或sinx=cosy=-1
cosx=siny=0
因此cos(x+y)=cosxcosy-sinxsiny=0
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