已知x+y=0.x+3y=1,求3x²+12xy+13y²的值
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已知x+y=0.x+3y=1,求3x²+12xy+13y²的值
![已知x+y=0.x+3y=1,求3x²+12xy+13y²的值](/uploads/image/z/13010220-36-0.jpg?t=%E5%B7%B2%E7%9F%A5x%2By%3D0.x%2B3y%3D1%2C%E6%B1%823x%26%23178%3B%2B12xy%2B13y%26%23178%3B%E7%9A%84%E5%80%BC)
3x²+12xy+13y²
=(x²+6xy+9y²)+(2x²+6xy+4y²)
=(x+3y)²+2(x+y)(x+2y)
=1+0
=1
=(x²+6xy+9y²)+(2x²+6xy+4y²)
=(x+3y)²+2(x+y)(x+2y)
=1+0
=1
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