根号2/2cos(2x+π/4)+sin^2 x 求化简过程
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根号2/2cos(2x+π/4)+sin^2 x 求化简过程
根号2/2cos(2x+π/4)+sin^2 x=1/2cos2x-1/2sin2x+1/2(1-cos2x)=1/2-1/2sin2x 求化简过程,谢谢
根号2/2cos(2x+π/4)+sin^2 x=1/2cos2x-1/2sin2x+1/2(1-cos2x)=1/2-1/2sin2x 求化简过程,谢谢
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cos(2x+π/4)=cosπ/4cos2x-sinπ/4sin2x
cosπ/4=sinπ/4=2分之根号2
cos2x=cosx^2-sinx^2=1-2sinx^2
sinx^2=(1-cos2x)/2
cosπ/4=sinπ/4=2分之根号2
cos2x=cosx^2-sinx^2=1-2sinx^2
sinx^2=(1-cos2x)/2
根号2/2cos(2x+π/4)+sin^2 x 求化简过程
求化简f(x)=sin^2x+2根号3sin(x+π/4)cos(x-π/4)-cos^2x-根号3
化简2sin^2[(π/4)+x]+根号3(sin^x-cos^x)-1
f(x)=sin平方x+2根号3sin(x+π/4)cos(x-π/4)-cos平方x-根号3
化简 1/2cos x-根号3/2sin x 根3sin x+cos x
已知函数f(x)=sin^2*x-根号3*sinπ/4*x*cosπ/4*x
sin(x+π/3)+2sin(x-π/3)-根号3cos(2π/3-x)
sin(5x)-sin(3x)= 根号2cos(4x)
化简:3/2cos x-(根号3)/2sin x
证明sin x+cos x的最大值等于 根号2
求不定积分:(根号cos(x))/(sin^2(x))
化简sin(x+π/2)分之1+根号二cos(2x-π/4)