根号下(1-2sin(派-2)cos(派-2) 怎么化简
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根号下(1-2sin(派-2)cos(派-2) 怎么化简
![根号下(1-2sin(派-2)cos(派-2) 怎么化简](/uploads/image/z/1274823-63-3.jpg?t=%E6%A0%B9%E5%8F%B7%E4%B8%8B%281-2sin%28%E6%B4%BE-2%29cos%28%E6%B4%BE-2%29+%E6%80%8E%E4%B9%88%E5%8C%96%E7%AE%80)
√[1-2sin(π-2)cos(π-2)]
=√(1+2sin2cos2)
=√(sin²2+2sin2cos2+cos²2)
=√(sin2+cos2)²
=|sin2+cos2|
∵ π/2
=√(1+2sin2cos2)
=√(sin²2+2sin2cos2+cos²2)
=√(sin2+cos2)²
=|sin2+cos2|
∵ π/2
根号下(1-2sin(派-2)cos(派-2) 怎么化简
化简根号下1+2sin(派-2).cos(派-2)得
化简根号下1+sin(派-2)*cos(派-2)
化简y=根号下(1+2sin(派-2)cos(派+2))
sin(x+派/3)+2sin(x-派/3)-根号3cos(2派/3-x)
4sin(3派-a)sin平方(1/2a+1/4派)-cos(派-2a)怎么化简
已知sin(派-a)-cos(派+a)=三分之根号二(派/2
化简4sin派/8*cos派/8*(cos^2派/8-sin^2派/8)
化简sin(派-x)+sin(派+x)-cos(-x)+cos(2派-x)-tan(派+x)cot(派-x)
已知函数f(x)=sin^2(x/2+派/12)+根号3sin(x/2+派/12)cos(x/2+派/12)-1/2.(
求证:2[1+sin(派+a)][1+cos(-a)]=[1-sin(派-a)-cos(派-a)]
[sin(A-派)cot(A-2派)]/[cos(A-派)tan(A-2派)]