证明下列各式:(1+tana+cota)/(1+tan^2 a+tana)-cota/(1+tan^2 a)=sinac
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:综合作业 时间:2024/07/25 13:23:07
证明下列各式:(1+tana+cota)/(1+tan^2 a+tana)-cota/(1+tan^2 a)=sinacosa
![证明下列各式:(1+tana+cota)/(1+tan^2 a+tana)-cota/(1+tan^2 a)=sinac](/uploads/image/z/12203-35-3.jpg?t=%E8%AF%81%E6%98%8E%E4%B8%8B%E5%88%97%E5%90%84%E5%BC%8F%3A%281%2Btana%2Bcota%29%2F%281%2Btan%5E2+a%2Btana%29-cota%2F%281%2Btan%5E2+a%29%3Dsinac)
(1+tana+cota)/(1+tan^2 a+tana)-cota/(1+tan^2 a)
=(1+sina/cosa+cosa/sina)/(1+sina^2/cosa^2 a+sina/cosa)
-cosa/sina/(1+sina^2/cosa^2 a)
=[(1+sina/cosa+cosa/sina)(1+sina^2/cosa^2 a)
-cosa/sina(1+sina^2/cosa^2 a+sina/cosa)]
/(1+sina^2/cosa^2 a+sina/cosa)(1+sina^2/cosa^2 a)
=sinacosa(1+sina^2/cosa^2 a+sina/cosa)(1+sina^2/cosa^2 a)
/(1+sina^2/cosa^2 a+sina/cosa)(1+sina^2/cosa^2 a)
=sinacosa
=(1+sina/cosa+cosa/sina)/(1+sina^2/cosa^2 a+sina/cosa)
-cosa/sina/(1+sina^2/cosa^2 a)
=[(1+sina/cosa+cosa/sina)(1+sina^2/cosa^2 a)
-cosa/sina(1+sina^2/cosa^2 a+sina/cosa)]
/(1+sina^2/cosa^2 a+sina/cosa)(1+sina^2/cosa^2 a)
=sinacosa(1+sina^2/cosa^2 a+sina/cosa)(1+sina^2/cosa^2 a)
/(1+sina^2/cosa^2 a+sina/cosa)(1+sina^2/cosa^2 a)
=sinacosa
证明下列各式:(1+tana+cota)/(1+tan^2 a+tana)-cota/(1+tan^2 a)=sinac
证明(tan^2a+tana+1)(cot^2a+cota+1)=tan^2a+cot^2a+1
求证(1+tan^2A)/(1+cot^2A)=(1-tanA/1-cotA)^2
证明 tanA-cotA=(1-2cos^2A)/(sinAcosA)
tan2A-tanA/tan2A+cotA=tan^2A 请问如何证明,
已知∠A为锐角,tanA-cotA=4,tan^2A+cot^2A=?
若tana+cota=a则tan^2a+cot^2a=
若tana-cota=2,则tan^2a+cot^2a=
已知tana+cota=3,则tan^2a+cot^2a=?
已知tana+cota=2,求下列各式的值(1)tan2a+cot2a(2)sina+cosa
若tana-cota=2,则tan^2+cot^2a=
已知tana+cota=9/4,则tan^2a+secacsca+cot^2的值