求向量组(1,2,3,4)^T,(2,3,4,5)^T,(3,4,5,6)^T,(4,5,6,7)^T的轶
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求向量组(1,2,3,4)^T,(2,3,4,5)^T,(3,4,5,6)^T,(4,5,6,7)^T的轶
![求向量组(1,2,3,4)^T,(2,3,4,5)^T,(3,4,5,6)^T,(4,5,6,7)^T的轶](/uploads/image/z/12125529-9-9.jpg?t=%E6%B1%82%E5%90%91%E9%87%8F%E7%BB%84%EF%BC%881%2C2%2C3%2C4%29%5ET%2C%EF%BC%882%2C3%2C4%2C5%29%5ET%2C%EF%BC%883%2C4%2C5%2C6%29%5ET%2C%EF%BC%884%2C5%2C6%2C7%29%5ET%E7%9A%84%E8%BD%B6)
(a1,a2,a3,a4) =
1 2 3 4
2 3 4 5
3 4 5 6
4 5 6 7
r4-r3,r3-r2,r2-r1
1 2 3 4
1 1 1 1
1 1 1 1
1 1 1 1
r1-r2,r3-r2,r4-r2
0 1 2 3
1 1 1 1
0 0 0 0
0 0 0 0
所以向量组的秩为2
1 2 3 4
2 3 4 5
3 4 5 6
4 5 6 7
r4-r3,r3-r2,r2-r1
1 2 3 4
1 1 1 1
1 1 1 1
1 1 1 1
r1-r2,r3-r2,r4-r2
0 1 2 3
1 1 1 1
0 0 0 0
0 0 0 0
所以向量组的秩为2
求向量组(1,2,3,4)^T,(2,3,4,5)^T,(3,4,5,6)^T,(4,5,6,7)^T的轶
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解方程:4:5t=2:(3t-1)
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