(1-1/2+1/3-1/4+1/5-1/6+.+1/99-1/100)/(1/102+1/104+1/106+.+1/
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/23 05:07:03
(1-1/2+1/3-1/4+1/5-1/6+.+1/99-1/100)/(1/102+1/104+1/106+.+1/200=?急
分子1-1/2+1/3-1/4+1/5-1/6+...+1/99-1/100
= (1+1/3+1/5+...+1/99)-(1/2+1/4+1/6+...+1/100)
= (1+1/2+1/3+1/4+1/5+1/6+...+1/99+1/100)-2×(1/2+1/4+1/6+...+1/100)
= (1+1/2+1/3+1/4+1/5+1/6+...+1/99+1/100)-(1+1/2+1/3+...+1/50)
= 1/51+1/52+1/53+...+1/99+1/100.
分母1/102+1/104+1/106+...+1/200
= 1/2×(1/51+1/52+1/53+...+1/100).
因此分子/分母 = 1/(1/2) = 2.
= (1+1/3+1/5+...+1/99)-(1/2+1/4+1/6+...+1/100)
= (1+1/2+1/3+1/4+1/5+1/6+...+1/99+1/100)-2×(1/2+1/4+1/6+...+1/100)
= (1+1/2+1/3+1/4+1/5+1/6+...+1/99+1/100)-(1+1/2+1/3+...+1/50)
= 1/51+1/52+1/53+...+1/99+1/100.
分母1/102+1/104+1/106+...+1/200
= 1/2×(1/51+1/52+1/53+...+1/100).
因此分子/分母 = 1/(1/2) = 2.
(1-1/2+1/3-1/4+1/5-1/6+.+1/99-1/100)/(1/102+1/104+1/106+.+1/
1-1/2+1/3-1/4+1/5-1/6+.+1/99-1/100○(1/102+1/104+1/106+...+1/
1/102+1/104+1/106+...+1/200分之1-1/2+1/3-1/4+1/5-1/6...+1/99-1
(1-1/2+1/3-1/4.+1/99-1/100 )÷(1/102+1/104+1/106+……+1/200)
1-1/2+1/3-1/4+1/5-1/6+…+1/99-1/100 1/(101+1)+1/(2+102)+1/(3+
(1-1/2+1/3-1/4+1/5-...+1/99-1/100)/[1/(1+101)+1/(2+102)+1/(3
1-1/2+1/3-1/4+...+1/99-1/100/1/1+101+1/2+102+1/3+103+...+1/5
1-1/2+1/3-1/4+1/5-1/6…+1/99-1/100)/(1/51+1/52+1/53+…+1/99+1/
(1-1/2)(1-1/3)(1-1/4).(1-1/99)(1-1/100)等于?
(1+1/1*3)*(1+1/2*4)*(1+1/3*5).(1+1/98*100)*(1+1/99*101)
(1+1/1+3)*(1+1/2*4)*(1+1/3*5)*.*(1+1/98*100)*(1+1/99*101)
(-1)+2+(-3)+4+(-5)+6+.+(-99)+100+(-101)+102