如图,已知在△ABC与△ADE中,AB=AC,AD=AE,且∠BAC=∠DAE,试说明:△ABD≌△ACE
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如图,已知在△ABC与△ADE中,AB=AC,AD=AE,且∠BAC=∠DAE,试说明:△ABD≌△ACE
因为角BAC=角DAC,所以角DAB=角EAC,又因为AD=AE,AB=AC,所以:△ABD≌△ACE(SAS)
如图,已知在△ABC与△ADE中,AB=AC,AD=AE,且∠BAC=∠DAE,试说明:△ABD≌△ACE
如图,在△ABC和△ADE中,AB=AC,AD=AE,∠BAC=∠DAE,求证:△ABD≌△ACE.
已知在三角形ABC与三角形ABD中AB=AC,AD=AE,且角BAC=角DAE,试说明三角形ABD≌三角形ACE
如图,等腰三角形ABC和等腰三角形ADE中,AB=AC,AD=AE,∠CAB=∠EAD,试说明:△ACE≌ΔABD
如图,AB=AC,AD=AE,∠BAC=∠DAE.求证:△ABD≌△ACE.
如图,在△ABC和△ADE中,AB=AC,AD=AE,若BD=CE,求证∠ABD=∠ACE
已知:如图①所示,在△ABC和△ADE中,AB=AC,AD=AE,∠BAC=∠DAE=α,且点B,A,D在一条直线上,连
已知:如图①所示,在△ABC和△ADE中,AB=AC,AD=AE,∠BAC=∠DAE,且点B,A,D在一条直线上,连接B
已知:如图①所示,在△ABC和△ADE中,AB=AC,AD=AE,∠BAC=∠DAE,且点B,A,D在一条直线上,连接B
解一道几何题,当中的已知:如图①所示,在△ABC和△ADE中,AB=AC,AD=AE,∠BAC=∠DAE=α,且点B,A
如图,在△ABC和△ADE中,AB=AC,AD=AE,∠BAC=∠DAE=90°.①求证:C
如图,在△ABC和△ADE中,AB=AC,AD=AE,∠BAC=∠DAE=90°.