u=x的siny次方二阶
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![u=x的siny次方二阶](/uploads/image/f/846958-22-8.jpg?t=u%3Dx%E7%9A%84siny%E6%AC%A1%E6%96%B9%E4%BA%8C%E9%98%B6)
dy/dx=-x/siny-sinydy=xdx两边取积分cosy=ln|x|+c再问:详细些再答:囧算错了-sinydy=xdxS-sinydy=Sxdxcosy=x^2/2+c再问:要一步一步来再
两边求导:cos(x+y)*(1+y')=cosx+cosy*y'y'=(cosx-cos(x+y))/(cos(x+y)-cosy)e^x+1=e^y*y'+y'y'=(e^x+1)/(e^y+1)
两边对x求两次导数:1-y'+1/2cosyy'=0;==>y'=1/(1-cosy/2)0-y''+1/2(y'(-siny)+cosyy'')=0==>y''=y'siny/(cosy-2)再将y
sinx+siny=1/3sinx=1/3-siny(siny)^2+(cosy)^2=1(cosy)^2=1-(siny)^2u=sinx-cos^2yu=(1/3-siny)-[1-(siny)^
t=1/3-sinx-cos^x=sin^x-sinx-2/3=(sinx-1/2)^2-11/12当sinx=1/2时siny为-1/6满足-1≤sinY≤1因为sinx+siny=1/3所以-2/
隐函数的导数求法~
x-y+1/2siny=0两边对x求导得1-y'+1/2cosy*y'=0y'=2/(2-cosy)y''=dy'/dx=(dy'/dy)*(dy/dx)=[-2/(2-cosy)²]*si
sinx+siny=1/3,sinx=1/3-sinysin²x=1/6-2siny/3+sin²yz=siny—cos^2x=siny+sin²x-1=siny+1/6
dsiny+de^x-dxy²=0cosydy+e^xdx-y²dx-2xydy=0cosydy-2xydy=y²dx-e^xdxdy/dx=(y²-e^x)/
u是已知量吗?y=u^2xy′=(u^2x)′=2x(u)^(2x-1)
变为dx/dy=-x+siny公式:对于y'=P(x)y+Q(x),通解为y=(∫{Q(x)e^[-∫P(x)dx]}dx+C)e^[∫P(x)dx]对于dx/dy=-x+siny,P(y)=-1,Q
对x求导得到1-y'+0.5cosy*y'=0所以y'=1/(1-0.5cosy)而继续求导得到y"=-1/(1-0.5cosy)^2*(0.5siny)*y'再代入y'即y"=-1/(1-0.5co
隐函数求导,就是先左右一起求微分,加个d,然后写出多少dx+多少dy=0,移项变成dy/dx=多少的形式就好了
x-y+1/2siny=0F(x,y)=y-x-1/2siny=0F,Fx,Fy在定义域的任意点都是连续的,F(0,0)=0Fy(x,y)>0f'(x)=-Fx(x,y)/Fy(x,y)=1/(1-1
两边关于x求导,注意y是x的函数y'cosy=[1/(x+y)]*(1+y').①解得y'=1/(x+y)÷[cosy-1/(x+y)].②对①两边关于x求导可得y''cosy-(y')²s
dy/dx=(y^2-e^x)/(cosy-2xy)
(1)sinx的取值范围是【-1,1】又siny=1/3-sinx所以可以得到siny的取值范围是【-2/3,4/3】又siny本身的取值范围是【-1,1】故可以得到siny的取值范围是【-2/3,1
siny=1/3-sinx则-1
再问:请问那个f12的二阶导数是怎么来的啊再答:前面两个都来自f1'对x的偏导数再问:哦再问:再问您一下,还是这道题,先对x再对y求二阶连续偏导怎么做啊再问:u先对x再对y再答:再问:多谢再问:请问最
要使等式有意义,则cosx>0,siny>0等式两边取自然对数有ylncosx=xlnsiny等式两边对x求导有d(ylncosx)/dx=d(xlnsiny)/dx[dy*lncosx+y*(1/c