先化简:x^2-4x 4 2x x^2-2x x^2 1
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![先化简:x^2-4x 4 2x x^2-2x x^2 1](/uploads/image/f/2039717-29-7.jpg?t=%E5%85%88%E5%8C%96%E7%AE%80%3Ax%5E2-4x+4+2x+x%5E2-2x+x%5E2+1)
原式=[(x+2)/(x^2-2x)-(x-1)/(x^2-4x+4)]÷2(x-4)/(x^3-2x^2)=[(x+2)/(x^2-2x)-(x-1)/(x-2)²)]*[x²(
你写的看不懂分子分母的代数式用括号括起来否则分不出来先通分【((x-2)(x+2)-x(x-1))/x(x+2)(x+2)】(x+2)/(x-4)=(x-4)/x(x+2)(x-4)=1/x(x+2)
(4x²-4x+2分之x)*(2x²-x)=(4x²-7x/2)*(2x²-x)=(x/2)(8x-7)(x)(2x-1)=x^2(8x-7)(2x-1)/2,
原式为:[(4x²+12x)/(x²+x-6)]/[(x-2)/(x+2)-(x+2)/(x-2)]=4x(x+3)/(x+3)(x-2)÷[(x-2)²-(x+2)
(x²-4x+4)/(x²-2x)÷(x-4/x)=(x-2)²/[x(x-2)]÷[(x²-4)/x]=(x-2)²/[x(x-2)]÷[(x+2)
[3x/(x-2)+x/(x+2)]/[x/(x²-4)]={[3x(x+2)+x(x-2)]/(x²-4)}/[x/(x²-4)]=[(4x²+4x)/(x&
x^2+(4x-3x^2)-(5x-6x^2)-2=x^2+4x-3x^2-5x+6x^2-2=4x^2-x-2=1-1/2-2=-3/2
=x^2+5x-1=1/9-5/3-1=-23/9
(-x平方+5+4x)+(5x-4+2x平方)=-x^2+5+4x+5x-4+2x^2=x^2+9x+1其中x=-2原式=(-2)^2+9*(-2)+1=4-18+1=-13
2x-6/4-4x+x^2÷x-3/x-2=-2x-7/2+x-3/x=-x-3/x-7/2=1+3-7/21/2
原式=2x²+x-3-4x²-4x-1+4x²+4x=2x²+x-4=8-2-4=2
[X*X/X-1-X+1]*2X-2/X*X-2X+1首先X*X/X-1-X+1通分得到(2x-1)/(x-1)4X*X-4X+1=0可以推出:(2x-1)^2=0;即2x-1=0;则上面刚刚化简所得
原式=[2x(x+2)-x(x-2)]/(x²-4)+x/(x²-4)=(x²+7x)/(x²-4)=[x(x+7)]/[(x+2)(x-2)]代入x=5原式=
x^3+2x^2+x/x^2+2x-8除以(x/x-2×x+1/x+4)=x(x^2+2x+1)/(x-2)(x+4)/(x(x+1)/(x-2)(x+4))=x(x+1)^2/(x-2)(x+4)*
[(x-2/x²+2x)-(x-1/x²+4x+4)]÷﹙x-4/x+2﹚=[(x-2/x(x+2)-(x-1/(x+2)²]÷﹙x-4/x+2﹚=[(x-2)(x+2)
(1)(x-1)(x+4)-(x-3)(x+2)=x²+3x-4-(x²-x-6)=x²+3x-4-x²+x+6=4x+2∴当x=1/3时,原式=4×(1/3)
能不能先用()把每个分数括起来?
(4x²-3x)-2(x²+2x-1)-(x²+x-1)=4x²-3x-2x²-4x+2-x²-x+1=(4x²-2x²
原式=〖(x+2)/x(x-2)-(x-1)/(x-2)^2〗÷〖(x-4)(x+4)/x(x+4)〗=〖(x+2)(x-2)-(x-1)x〗/x(x-2)^2〗÷〖(x-4)(x+4)/x(x+4)