计算[4(x-2)2+12(x+2)(x-2)-8(x+1)2(x-2)]÷[4(x-2)]=______.
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计算[4(x-2)2+12(x+2)(x-2)-8(x+1)2(x-2)]÷[4(x-2)]=______.
![计算[4(x-2)2+12(x+2)(x-2)-8(x+1)2(x-2)]÷[4(x-2)]=______.](/uploads/image/z/6099248-56-8.jpg?t=%E8%AE%A1%E7%AE%97%5B4%EF%BC%88x-2%EF%BC%892%2B12%EF%BC%88x%2B2%EF%BC%89%EF%BC%88x-2%EF%BC%89-8%EF%BC%88x%2B1%EF%BC%892%EF%BC%88x-2%EF%BC%89%5D%C3%B7%5B4%EF%BC%88x-2%EF%BC%89%5D%3D______%EF%BC%8E)
原式=[4(x-2)2+12(x+2)(x-2)-8(x+1)2(x-2)]×
1
4(x−2)
=(x-2)+3(x+2)-2(x+1)2=x-2+3x+6-2x2-4x-2
=-2x2+2.
故答案为-2x2+2.
1
4(x−2)
=(x-2)+3(x+2)-2(x+1)2=x-2+3x+6-2x2-4x-2
=-2x2+2.
故答案为-2x2+2.
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