求1/x(x+1)+2/(x+1)(x+3)+3/(x+3)(x+6)的值
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求1/x(x+1)+2/(x+1)(x+3)+3/(x+3)(x+6)的值
![求1/x(x+1)+2/(x+1)(x+3)+3/(x+3)(x+6)的值](/uploads/image/z/2669978-2-8.jpg?t=%E6%B1%821%2Fx%28x%2B1%29%2B2%2F%28x%2B1%29%28x%2B3%29%2B3%2F%28x%2B3%29%28x%2B6%29%E7%9A%84%E5%80%BC)
1/x(x+1)+2/(x+1)(x+3)+3/(x+3)(x+6)
=1/x-1/(x+1)+1/(x+1)-1/(x+3)+1/(x+3)-1/(x+6)
= 1/x-1/(x+6)
=(x+6-x)/[x(x+6)]
=6/[x(x+6)]
=1/x-1/(x+1)+1/(x+1)-1/(x+3)+1/(x+3)-1/(x+6)
= 1/x-1/(x+6)
=(x+6-x)/[x(x+6)]
=6/[x(x+6)]
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