速解1题:(a+1)(a-4)—4(a-1)²
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/08/05 03:14:55
速解1题:(a+1)(a-4)—4(a-1)²
![速解1题:(a+1)(a-4)—4(a-1)²](/uploads/image/z/20325925-37-5.jpg?t=%E9%80%9F%E8%A7%A31%E9%A2%98%EF%BC%9A%28a%2B1%29%28a-4%29%E2%80%944%EF%BC%88a-1%29%26%23178%3B)
(a+1)(a-4)—4(a-1)²
=a²-4a+a-4-4(a²-2a+1)
=a²-4a+a-4-4a²+8a-4
=-3a²+5a-8
=a²-4a+a-4-4(a²-2a+1)
=a²-4a+a-4-4a²+8a-4
=-3a²+5a-8
(a²+a+1-a³/a-1)×(1+a-4a/1+a)
计算:(a+2/a²-2a-a-1/a²-4a+4)÷a-4/a
求数列1,a+a²,a²+a³+{a}^{4},a³+{a}^{4}+{a}^{
a(a-1)(a-2)(a-3)(a-4)因式分解
【1】a+a=a×a a= [ ]【2】a×a=a÷a a=[ ]【3】a×a=a-a a=[ ] [4]a-a=a+a
1/a+1-a+2/a²-1·a²-2a+1/a²+4a+4.
(4a²-3a)+(2+4a-a²)-(2a²+a-1),其中a=-2
已知A=4a²-3a,B=2a²+a-1,求A-2(A-B)
(a+2a分之a-2 - a²+4a+4分之a-1,其中a=3 先化简再求值
a^4+a^3-a-1(因式分解)
已知a=根号2-1,先化简√a²-2a+1/a²-a+a-1/a²-2a+1+4a
化简(1 - 1/a-1)÷a²-4a+4/a²-a