设集合A={x│(x-3)(x-a)=0,a∈R},B={x│(x-4)(x-1)=0},求A∪B,A∩B,最好有过程,
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:综合作业 时间:2024/07/26 20:05:45
设集合A={x│(x-3)(x-a)=0,a∈R},B={x│(x-4)(x-1)=0},求A∪B,A∩B,最好有过程,
A ={x│(x-3)(x-a)=0,a∈R}
={3,a}
B ={x│(x-4)(x-1)=0}
= {1,4}
A∪B = {3,a}∪{1,4}
= {1,3,4,a,a∈R }
= R (∵ a is any real number )
A∩B = {3,a}∩{1,4}
= {1,4}
={3,a}
B ={x│(x-4)(x-1)=0}
= {1,4}
A∪B = {3,a}∪{1,4}
= {1,3,4,a,a∈R }
= R (∵ a is any real number )
A∩B = {3,a}∩{1,4}
= {1,4}
设集合A={x|(x-3)(x-a)=0,a∈R},B={(x-4)(x-1)=0},求A∪B.
设集合A={x|(x-3)(x-a)=0,a属于R},B={x|(x-4)(x-1)=0},求A交B
一、设集合A={X|(X-3)(X-a)=0,a∈R};B={X|(X-4)(X-1)=0}.求①A∪B、②A∩B
设集合A={X|(X-3)(X-a)=0,a∈R},B={X|(X-4)(X-1)=0},求A∪B,A∩B.
设集合A={x|(x-3)(x-a)=0,a∈R},B={x|(x-4)(x-1)=0},求A∪B,A∩B.
·设集合A={x/(x-3)(x-a),A∈R} ,B={x/(x-4)(x-1)=0}求AuB,AnB
一元2次集合的运算设集合A = X丨(X-3)(X-a)=0 ,a∈R ,集合B=X丨(X-4)(X-1)=0 求A∪B
设集合A={xl(x-3)(x-a)=0,a∈R},B={xl(x-4)(x-1)=0},设A∪B,A∩B,已知答案,求
设集合A={χ|(x-3)(x-a)=0,a∈R},B={x|(x-4)(x-1)=0},求A∪Be,A∩B
设集合A={x|(x+3)(x-a)=0,a∈R},B={x|(x-4)(x-1)=0),求A U B,A n B.
设集合A={x|(x-3)(x-a)=0,a∈R},B={x|(x-1)(x-4)=0}
设集合A={xl(x-3)(x-a)=0,a∈R},B={xl(x-4)(x-1)=0},求A∪B,A∩B