1/2x1/n+1x1/n+2怎么等于1/2(1/n+1-1/n+2)
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1/2x1/n+1x1/n+2怎么等于1/2(1/n+1-1/n+2)
![1/2x1/n+1x1/n+2怎么等于1/2(1/n+1-1/n+2)](/uploads/image/z/20315400-24-0.jpg?t=1%2F2x1%2Fn%2B1x1%2Fn%2B2%E6%80%8E%E4%B9%88%E7%AD%89%E4%BA%8E1%2F2%EF%BC%881%2Fn%2B1-1%2Fn%2B2%EF%BC%89)
1/2x1/(n+1)x1/(n+2)
=1/2x1/((n+1)(n+2))
[由1=(n+2)-(n+1)]
=1/2x((n+2)-(n+1))/((n+1)(n+2))
乘法分配
=1/2x[(n+2)/((n+1)(n+2))-(n+1)/((n+1)(n+2))]
分子分母约去
=1/2x[1/(n+1)-1/(n+2)]
还有,梓萌是什么情况
=1/2x1/((n+1)(n+2))
[由1=(n+2)-(n+1)]
=1/2x((n+2)-(n+1))/((n+1)(n+2))
乘法分配
=1/2x[(n+2)/((n+1)(n+2))-(n+1)/((n+1)(n+2))]
分子分母约去
=1/2x[1/(n+1)-1/(n+2)]
还有,梓萌是什么情况
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