已知sinβ=三分之一,sin(α+β)=1,则sin(2α+β)=多少?
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/08/08 15:16:37
已知sinβ=三分之一,sin(α+β)=1,则sin(2α+β)=多少?
![已知sinβ=三分之一,sin(α+β)=1,则sin(2α+β)=多少?](/uploads/image/z/20314835-35-5.jpg?t=%E5%B7%B2%E7%9F%A5sin%CE%B2%3D%E4%B8%89%E5%88%86%E4%B9%8B%E4%B8%80%2Csin%28%CE%B1%2B%CE%B2%29%3D1%2C%E5%88%99sin%282%CE%B1%2B%CE%B2%29%3D%E5%A4%9A%E5%B0%91%3F)
sin(α+β)=1,
cos(α+β)=0,
sinβ=1/3,
sin(2α+β)
=sin(2α+2β-β)
=sin(2α+2β)cosβ-sinβcos(2α+2β)
=2sin(α+β)cos(α+β)cosβ-sinβ[1-2sin^2(α+β)]
=0+1/3[1-2]
=-1/3
cos(α+β)=0,
sinβ=1/3,
sin(2α+β)
=sin(2α+2β-β)
=sin(2α+2β)cosβ-sinβcos(2α+2β)
=2sin(α+β)cos(α+β)cosβ-sinβ[1-2sin^2(α+β)]
=0+1/3[1-2]
=-1/3
已知sin(α+β)=2/3,sin(α-β)=3/5,sinα+sinβ=1/2,求cos[(α+β)/2]*sin[
已知sin(2α+ β)=5sinβ,求证:2sin(α+ β)=3sinα
已知α,β都是锐角,若(sinα+sinα)^2=2sinβ+1/2sinβ则α+β为 答案是75度,
已知3sin^2α—2sinα+2sin^2β=0 求sin^2α+sin^2β的取值范围
已知3(sinα)^2-2sinα+2(sinβ)^2=0,试求(sinα)^2+(sinβ)^2的取值范围
已知:3sin^2α+2sin^2β=2sinα,求sin^2α+sin^2β的值
已知3sin²α-2sinα+2sin²β=0,试求sin²α+sin²β的取值
三角函数的方程已知3sin²α+2sin²β=2sinα,求sin²α+sin²
求证sin^2α+sin^2β-sin^2αsin^2β+cos^2cos^2β=1
求证 sinαcosβ=1/2[sin(α+β)+sin(α-β)]
已知sin(α+β)=1/2,sin(α-β)=1/3 (1)求证:sinα*cosβ=5cosα*sinβ
已知α,β为锐角,且3sin²α+2sin²β=1,3sin²α-2sin(2β)=0,求