化简 {sin(π+α)cos(α-2π)tan9π/4}/sin(-α)sin(7π/2+α)
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化简 {sin(π+α)cos(α-2π)tan9π/4}/sin(-α)sin(7π/2+α)
过程
过程
![化简 {sin(π+α)cos(α-2π)tan9π/4}/sin(-α)sin(7π/2+α)](/uploads/image/z/20287159-7-9.jpg?t=%E5%8C%96%E7%AE%80+%7Bsin%28%CF%80%2B%CE%B1%29cos%28%CE%B1-2%CF%80%29tan9%CF%80%2F4%7D%2Fsin%28-%CE%B1%29sin%287%CF%80%2F2%2B%CE%B1%29)
[sin(π+a)cos(a-2π)tan9π/4]/sin(-a)sin(7π/2+a)
=[-sinacosatan(π/4+2π)]/-sinasin(3π/2+2π+a)
=(-sinacosa)/-sina(-cosa)
=-1
=[-sinacosatan(π/4+2π)]/-sinasin(3π/2+2π+a)
=(-sinacosa)/-sina(-cosa)
=-1
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比较大小sin(cosα)与cos(sinα)(0<α<π/2)
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cos2α/[sin(α-π/4)]=-根号2 /2,cosα+sinα=?
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(sinα/2+cosα/2)^2+2sin^2(π/4-α/2)=
sinα+cosα=√2sin(α+π/4)是公式吗?