(m+n)!/(m+n-2)!-n!/(n-2)!=62怎么化简成 m(m+2n-1)=62 求详解
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/26 17:50:17
(m+n)!/(m+n-2)!-n!/(n-2)!=62怎么化简成 m(m+2n-1)=62 求详解
![(m+n)!/(m+n-2)!-n!/(n-2)!=62怎么化简成 m(m+2n-1)=62 求详解](/uploads/image/z/20195568-0-8.jpg?t=%EF%BC%88m%2Bn%EF%BC%89%21%2F%EF%BC%88m%2Bn-2%EF%BC%89%21-n%21%2F%EF%BC%88n-2%EF%BC%89%21%3D62%E6%80%8E%E4%B9%88%E5%8C%96%E7%AE%80%E6%88%90+m%EF%BC%88m%2B2n-1%EF%BC%89%3D62+%E6%B1%82%E8%AF%A6%E8%A7%A3)
(m+n)!/(m+n-2)!-n!/(n-2)!
=(m+n)(m+n-1)(m+n-2)!/(m+n-2)!-n(n-1)(n-2)!/(n-2)!
=(m+n)(m+n-1)-n(n-1)
=m^2+mn-m+mn+n^2-n-n^2+n
=m^2+2mn-m
= m(m+2n-1)
=(m+n)(m+n-1)(m+n-2)!/(m+n-2)!-n(n-1)(n-2)!/(n-2)!
=(m+n)(m+n-1)-n(n-1)
=m^2+mn-m+mn+n^2-n-n^2+n
=m^2+2mn-m
= m(m+2n-1)
已知m/n=5、,求(m/(m+n))+(m/(m-n))-(n^2/(m^3-n^2))
已知:m*m=n+2,n*n=m+2.求m*m*m-2mn+n*n*n(m不等于n).
m(m+2n-1)=62怎么求m和n的值?
已知|2m-n/m+2n|=3,求2(2m-n)/m+2n-2m-n/m+2n-3的值
若2m-n/m+2n=5,求3(2m-n)/m+2n-m+2n/2m-n+3的值
2x+n/m=m/n-(m/n+n/m)x(m+n不等于0)
已知:2m-5n=0 求下式的值 (1+n/m-m/m-n)/(1+n/m-m/m-n)
(m+n)(m-n)-(1-2n)化简
已知m/n = 5/3 求m/(m+n)+m/(m-n)-n^2/(m^2-n^2)等于多少?(要化简全过程)
化简m/(m+n)²+n/m²-n²-2n²/(m+n)(m²-n
是否存在正整数m,n,使得m(m+2)=n(n+1)?
若m-n=3,3m+2n=2,求代数式6m(m-n)-4n(n-m)的值