初中分式方程.[x+1/(x-1)]+[2/(x+2)]=1
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初中分式方程.[x+1/(x-1)]+[2/(x+2)]=1
[x+1/(x-1)]+[2/(x+2)]=1
[x+1/(x-1)]+[2/(x+2)]=1
![初中分式方程.[x+1/(x-1)]+[2/(x+2)]=1](/uploads/image/z/20184504-24-4.jpg?t=%E5%88%9D%E4%B8%AD%E5%88%86%E5%BC%8F%E6%96%B9%E7%A8%8B.%5Bx%2B1%2F%28x-1%29%5D%2B%5B2%2F%28x%2B2%29%5D%3D1)
两边乘(x-1)(x+2)
x²+3x+2+2x-2=x²+x-2
5x=x-2
x=-1/2
经检验,x=-1/2是方程的解
x²+3x+2+2x-2=x²+x-2
5x=x-2
x=-1/2
经检验,x=-1/2是方程的解
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