解不等式(1)(y+1/6)-(2y-5/4)>=1+(y/2) (2)(x-3/2)+3>=x 1-3(x-1)
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解不等式(1)(y+1/6)-(2y-5/4)>=1+(y/2) (2)(x-3/2)+3>=x 1-3(x-1)
![解不等式(1)(y+1/6)-(2y-5/4)>=1+(y/2) (2)(x-3/2)+3>=x 1-3(x-1)](/uploads/image/z/20183193-9-3.jpg?t=%E8%A7%A3%E4%B8%8D%E7%AD%89%E5%BC%8F%281%29%28y%2B1%2F6%29-%282y-5%2F4%29%3E%3D1%2B%28y%2F2%29+%282%29%28x-3%2F2%29%2B3%3E%3Dx+1-3%28x-1%29)
第一题
两边乘12
2(y+1)-3(2y-5)>=12+6y
-4y+17>=12+6y
10y=2x
x
两边乘12
2(y+1)-3(2y-5)>=12+6y
-4y+17>=12+6y
10y=2x
x
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
先化简再求值(x-y)(x+y)-(x-2y) 的完全平方+x(3x-5y)-(x-y)(x-2y),其中x=1/2 y
化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1
已知x=1/3,y=-1/2,求代数式x-(x+y)+(x+2y)-(x+3y)+(x+4y)-(x+5y)+...-(
解方程组:2(x-y)/3-x+y/4=-1 ,6(x+y)-4(2x-y)=16
解二元一次方程组{3(x+y)-4(x-y)=4,x+y/2+x-y/6=1
解方程组3(x+y)-4(x-y)=4和(x+y)/2+(x-y)/6=1
解二元一次方程组{3(x+y)-(x-y)=4,x+y/2+x-y/6=1
解二元一次方程组:3(x+y)-4(x-y)=4,x+y/2+x-y/6+1
(3x-y)^2+(3x+y)(3x-y),x=1,y=-2
(x+2)(x+3) (x-4)(x+1) (y+4)(y-2) (y-5)(y-3)
3x+2y/4=2x+y/5=x-y+1/6