2(x∧2-xy)-3(2x∧2-3xy)-2[x∧2(2x∧2-xy+y∧2)]
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2(x∧2-xy)-3(2x∧2-3xy)-2[x∧2(2x∧2-xy+y∧2)]
![2(x∧2-xy)-3(2x∧2-3xy)-2[x∧2(2x∧2-xy+y∧2)]](/uploads/image/z/20177116-52-6.jpg?t=2%28x%E2%88%A72%EF%BC%8Dxy%29-3%EF%BC%882x%E2%88%A72-3xy%29-2%5Bx%E2%88%A72%282x%E2%88%A72-xy%2By%E2%88%A72%29%5D)
-2[x∧2(2x∧2-xy+y∧2)] 这里中间漏掉一个加号或者减号了吧
我按照-2[x∧2-(2x∧2-xy+y∧2)]
原式
=2x²-2xy-6x²+9xy-2x²+2(2x²-xy+y²)
=2x²-2xy-6x²+9xy-2x²+4x²-2xy+2y²
=(2x²-2x²+4x²-6x²)-(2xy+2xy-9xy)+2y²
=-2x²+5xy+2y²
我按照-2[x∧2-(2x∧2-xy+y∧2)]
原式
=2x²-2xy-6x²+9xy-2x²+2(2x²-xy+y²)
=2x²-2xy-6x²+9xy-2x²+4x²-2xy+2y²
=(2x²-2x²+4x²-6x²)-(2xy+2xy-9xy)+2y²
=-2x²+5xy+2y²
(xy-x^2)乘以(xy)/(x-y)
(-1/3xy)∧2*[3xy(2x-y)-3x(2xy-4y∧2)]
(x-2xy)*(-xy+2y*y)-(3x*x-2xy)(x-9xy+6y*y)
计算3xy[2xy-x(y-2)+x-1]
计算:3xy[2xy-x(y-2)+x]
(-3x^y+2xy)-( )=4x^+xy
(x^2+xy/x-y)/(xy/x-y)计算
分解因式:(X+Y-2XY)*(X+Y-2)+(1-XY)∧2
因式分解:(2x-y)(x^2+xy-2y^2) xy(x^2-xy)(-3xy^2)
由已知x+y=-2,xy=3那么2(x+xy)-[(xy-3y)-x]-(-xy)等于多少?
x^2-xy-6y^2+3xy+y+2
x^3y(-4y)^2+(-7xy)^2*(-xy)-5xy^3*(-3x)^2