设x/3=y/5=z/7,则x+y/y=? y+3x/3y-2z=?
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设x/3=y/5=z/7,则x+y/y=? y+3x/3y-2z=?
![设x/3=y/5=z/7,则x+y/y=? y+3x/3y-2z=?](/uploads/image/z/20156129-17-9.jpg?t=%E8%AE%BEx%2F3%3Dy%2F5%3Dz%2F7%2C%E5%88%99x%2By%2Fy%3D%3F+y%2B3x%2F3y-2z%3D%3F)
x/3=y/5=z/7
x+y/y
=x/y+1
=3/5+1
=8/5
y+3x/3y-2z
=5x/3+3x/3*(5x/3)-2*(7x/3)
=(14x/3)/(x/3)
=14
x+y/y
=x/y+1
=3/5+1
=8/5
y+3x/3y-2z
=5x/3+3x/3*(5x/3)-2*(7x/3)
=(14x/3)/(x/3)
=14
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
x/2=y/3=z/5 x+3y-z/x-3y+z
2x+5y+4z=0,3x+y-7z=0,则x+y-z=?
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