5(y-2)-7(y+3)=11(y+4)
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5(y-2)-7(y+3)=11(y+4)
![5(y-2)-7(y+3)=11(y+4)](/uploads/image/z/20148503-23-3.jpg?t=5%28y-2%29-7%28y%2B3%29%3D11%28y%2B4%29)
5(y-2)-7(y+3)=11(y+4)
5y-10-7y-21=11y+44
-2y-31=11y+44
13y=-75
y=-75/13
5y-10-7y-21=11y+44
-2y-31=11y+44
13y=-75
y=-75/13
(2y-3)(-y+4)=(y-2)(y-5)-3y(y-7/3)解方程
3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27
10y+2(7y-2)=5(4y+3)+3y怎么算
3x+2=y 5X+4=Y 7X+6=Y 9X+8=y 11x=y要如何计算
3x+2=y 5x+4=y 7x+6=y 9x+8=y 11x=y
y-3x=2,y-5x=4,y-7x=6,y-9x=8,y-11x=0方程组,
3x+2=y 5x+4=y 7x+6=y 9x+8=y 11x=y 联立方程 有的话
{3x-2y=3,2x+2y=17 {4x-2y=14,5x+y=7 {x+3y=6,2x-3y=3 {2x+3y=11
已知4x²y-3y²=7,3x²y+4y²=19,求11x²y-2y&
{2x+y/3-2y=0 2(2x+y)-5=7y
解3y+5/3y-6=1/2+5y-4/2y-4
代数式4y² - 2y + 5 = 7,那么代数式2y² - y + 1