1 (x + 1/x-1)/ x/x^2-1*1/x^2+2x+1;其中x=2; 2 2x-4/x^2-4 / 2x/x
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1 (x + 1/x-1)/ x/x^2-1*1/x^2+2x+1;其中x=2; 2 2x-4/x^2-4 / 2x/x+2-1/x-1;其中x=5;多谢各位了,感激不尽,总觉得很难,麻烦把过程写清楚,我好理解,急,[注:x^2代表x的平方;/代表分数线或除号],
![1 (x + 1/x-1)/ x/x^2-1*1/x^2+2x+1;其中x=2; 2 2x-4/x^2-4 / 2x/x](/uploads/image/z/20146941-45-1.jpg?t=1+%28x+%2B+1%2Fx-1%29%2F+x%2Fx%5E2-1%2A1%2Fx%5E2%2B2x%2B1%3B%E5%85%B6%E4%B8%ADx%3D2%3B+2+2x-4%2Fx%5E2-4+%2F+2x%2Fx)
1
(X+1)/(X-1)*(X+1)(X-1)/X*1/(X+1)方
=1/X
=1/2
2
2(X-2)/[(X+2)(X-2)]*(X+2)/2X-1/(X-1)
=1/X-1/(X-1)
=1/5-1/4
=-1/20
(X+1)/(X-1)*(X+1)(X-1)/X*1/(X+1)方
=1/X
=1/2
2
2(X-2)/[(X+2)(X-2)]*(X+2)/2X-1/(X-1)
=1/X-1/(X-1)
=1/5-1/4
=-1/20
x^5+x^4 = (x^3-x)(x^2+x+1)+x^2+x
(X+4)(x-2)(x-4),其中x=-1
x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4
|X-1|+|X-2|+|X-3|+|X-4|+|X-5|+|X-6|+|X-7|+|X-8|+|X-9|+|X-10|
解方程(x/x(x+2))+(x/(x+2)(x+4))+.+x/(x+8)(x+10)=1
x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^2002
化简求值 已知[x-(x/x+1)]*(x+1/x^2+3x+2)除以(x^2-2x/x^2-4),其中x=-1/2
x/x平方-x+2=2x/x+1
先化简再求值先化简再求值:(x-x/x+1)(x+1/x^2+4x+4)(x^2-4/x^2-2x),其中x=-0.5
先化简,再求值:x^3+2x^2+x/x^2+2x-8除以(x/x-2 × x+1/x+4),其中x=负5/4
先化简再求值:2x²-4x/x+2·x²+2x/x²-4x+4+4x/2-x,其中x=1/
x-1)(X-2)(x-3)...(x-50)+x(x-2)(X-3)...(X-50)+...+x(x-1)(x-2)