ax^2+3ax-1因式分解
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ax^2+3ax-1因式分解
![ax^2+3ax-1因式分解](/uploads/image/z/20139344-8-4.jpg?t=ax%5E2%2B3ax-1%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3)
解ax²+3ax-1=0得
x1=(-3a+根号(9a²+4a))/2a x2=(-3a-根号(9a²+4a))/2a
∴ax²+3ax-1
=a(x-x1)(x-x2)
x1=(-3a+根号(9a²+4a))/2a x2=(-3a-根号(9a²+4a))/2a
∴ax²+3ax-1
=a(x-x1)(x-x2)