tan19°+tan26°+tan19°tan26°=______.
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/16 06:26:19
tan19°+tan26°+tan19°tan26°=______.
![tan19°+tan26°+tan19°tan26°=______.](/uploads/image/z/20138413-13-3.jpg?t=tan19%C2%B0%2Btan26%C2%B0%2Btan19%C2%B0tan26%C2%B0%3D______%EF%BC%8E)
∵tan45°=tan(19°+26°)=
tan19°+tan26°
1−tan19°tan26°=1,
∴tan19°+tan26°=1-tan19°tan26°,
则tan19°+tan26°+tan19°tan26°=1-tan19°tan26°+tan19°tan26°=1.
故答案为:1
tan19°+tan26°
1−tan19°tan26°=1,
∴tan19°+tan26°=1-tan19°tan26°,
则tan19°+tan26°+tan19°tan26°=1-tan19°tan26°+tan19°tan26°=1.
故答案为:1
求下列三角函数值(1)cos-1109°(2)sin-1050°(3)tan19π/3
3.76°=______度 ______分 ______秒.
27.24°=______度______分______秒,108°21′36″=______度.
22.5°=______度______分;12°24′=______度.
45°=______直角=______平角=______周角.
用度、分、秒表示26.34°=______度______分______秒.
计算:57.32°=______度______分______秒.
(1)39.56°=______°______′______″(2)65°25′12″=______°.
39.145°=______度______分_______秒
(1)34.37°=______度______分______秒. (2)3
52°45′-32°46′=______°______′.
计算:33°52′+21°54′=______度______分.