请问这是如何变的 2cosa (sina+cosa)+1→√2sin(2a+π/4)+2
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请问这是如何变的 2cosa (sina+cosa)+1→√2sin(2a+π/4)+2
![请问这是如何变的 2cosa (sina+cosa)+1→√2sin(2a+π/4)+2](/uploads/image/z/20119600-64-0.jpg?t=%E8%AF%B7%E9%97%AE%E8%BF%99%E6%98%AF%E5%A6%82%E4%BD%95%E5%8F%98%E7%9A%84+2cosa+%28sina%2Bcosa%29%2B1%E2%86%92%E2%88%9A2sin%282a%2B%CF%80%2F4%29%2B2)
2cosa (sina+cosa)+1
=2cosasina+2cosa^2+1
=sin2a+2cosa^2-1+2
=sin2a+cos2a+2
=√2(根号2/2sin2a+根号2/2cos2a)+2
=√2(sin2acos45+cos2asin45)+2
=√2sin(2a+π/4)+2
=2cosasina+2cosa^2+1
=sin2a+2cosa^2-1+2
=sin2a+cos2a+2
=√2(根号2/2sin2a+根号2/2cos2a)+2
=√2(sin2acos45+cos2asin45)+2
=√2sin(2a+π/4)+2
(2sin^2a+sin2a)/(1+tana) 整理 =[2sina(sina+cosa)]/[(sina+cosa)
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