有理数除法,是强项的来,要正确的 我会给高分的
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有理数除法,是强项的来,要正确的 我会给高分的
刚才死机了
①-5÷(-1/5)×(-2/9)+|-1/9|
②[(+1/7)-(-1/3)-(+1/5)]÷(-1/105)
③[1又1/24-(3/8+1/6-3/4)×24]÷(-5)
④(-11又3/2)÷2-(-20又1/2)÷2+10.5÷2
⑤(1/2003-1)×(1/2002-1)×(1/2001-1)×......×(1/1001-1)×(1/1000-1)
⑥(-1/42)÷(1/6-2/14+2/3-2/7)
刚才死机了
①-5÷(-1/5)×(-2/9)+|-1/9|
②[(+1/7)-(-1/3)-(+1/5)]÷(-1/105)
③[1又1/24-(3/8+1/6-3/4)×24]÷(-5)
④(-11又3/2)÷2-(-20又1/2)÷2+10.5÷2
⑤(1/2003-1)×(1/2002-1)×(1/2001-1)×......×(1/1001-1)×(1/1000-1)
⑥(-1/42)÷(1/6-2/14+2/3-2/7)
![有理数除法,是强项的来,要正确的 我会给高分的](/uploads/image/z/20105720-8-0.jpg?t=%E6%9C%89%E7%90%86%E6%95%B0%E9%99%A4%E6%B3%95%2C%E6%98%AF%E5%BC%BA%E9%A1%B9%E7%9A%84%E6%9D%A5%2C%E8%A6%81%E6%AD%A3%E7%A1%AE%E7%9A%84+%E6%88%91%E4%BC%9A%E7%BB%99%E9%AB%98%E5%88%86%E7%9A%84)
题目呢?
再问: 好了,题目写好了
再答: ①-5÷(-1/5)×(-2/9)+|-1/9| =25*(-2/9)+1/9 =-50/9+1/9 =-49/9 ②[(+1/7)-(-1/3)-(+1/5)]÷(-1/105) =[1/7+1/3)-1/5]÷(-1/105) =(15+35-21)/105÷(-1/105) =-29 ③[1又1/24-(3/8+1/6-3/4)×24]÷(-5) =[25/24-(9+4-18)]÷(-5) =-5/24-1 =-29/24 ④(-11又3/2)÷2-(-20又1/2)÷2+10.5÷2 =-25/4+41/4+21/4 =37/4 ⑤(1/2003-1)×(1/2002-1)×(1/2001-1)×......×(1/1001-1)×(1/1000-1) =2002/2003×2001/2002×2000/2001×....×1000/1001×999/1000 =999/2003 ⑥(-1/42)÷(1/6-2/14+2/3-2/7) =(-1/42)÷(7-6+28-12)/42 =-1/17
再问: 好了,题目写好了
再答: ①-5÷(-1/5)×(-2/9)+|-1/9| =25*(-2/9)+1/9 =-50/9+1/9 =-49/9 ②[(+1/7)-(-1/3)-(+1/5)]÷(-1/105) =[1/7+1/3)-1/5]÷(-1/105) =(15+35-21)/105÷(-1/105) =-29 ③[1又1/24-(3/8+1/6-3/4)×24]÷(-5) =[25/24-(9+4-18)]÷(-5) =-5/24-1 =-29/24 ④(-11又3/2)÷2-(-20又1/2)÷2+10.5÷2 =-25/4+41/4+21/4 =37/4 ⑤(1/2003-1)×(1/2002-1)×(1/2001-1)×......×(1/1001-1)×(1/1000-1) =2002/2003×2001/2002×2000/2001×....×1000/1001×999/1000 =999/2003 ⑥(-1/42)÷(1/6-2/14+2/3-2/7) =(-1/42)÷(7-6+28-12)/42 =-1/17