2(290-50x)+10=190+10x咋算
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2(290-50x)+10=190+10x咋算
![2(290-50x)+10=190+10x咋算](/uploads/image/z/20036647-55-7.jpg?t=2%EF%BC%88290-50x%EF%BC%89%2B10%3D190%2B10x%E5%92%8B%E7%AE%97)
580-100x+10=190+10x
-110x=-400
x=40/11
-110x=-400
x=40/11
(x+12)(x-2)+(x+7)(x+8)-(x+5)(x-10),其中x=2
解方程.(5x/x²+x-6)+(2x-5/x²-x-12)=7x-10/x²-6x+8
解方程(x/x(x+2))+(x/(x+2)(x+4))+.+x/(x+8)(x+10)=1
(2x-2)(x-1)=0 x(x-5)=5x-10
(X-X*20%-18-(X-X*20%-18)*10%=X*1/2-3(过程)
2x(56-X)-10=30+X
x+2x×10=10x+2x+36
y=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10)的导数在x=1
设函数f(x)=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10),
计算:1/(x^2-7x+10)+1/(x^2-x-2)+1/(x^2+5x+4)+1/(x^2+11x+28)=( )
(1)当x=2时,求代数式2x²(x²-x+1)-x(2x³-10x²+2x)的
(x+1分之x+6)-(x^+3x+2分之3x^+10x+4)+(x+2分之2x+1)=0,解这个方程