一题分式混合运算[x-1/x²-x-2]÷x²-2x+1/2-x÷[1/x²+x]
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一题分式混合运算
[x-1/x²-x-2]÷x²-2x+1/2-x÷[1/x²+x]
[x-1/x²-x-2]÷x²-2x+1/2-x÷[1/x²+x]
![一题分式混合运算[x-1/x²-x-2]÷x²-2x+1/2-x÷[1/x²+x]](/uploads/image/z/19969432-16-2.jpg?t=%E4%B8%80%E9%A2%98%E5%88%86%E5%BC%8F%E6%B7%B7%E5%90%88%E8%BF%90%E7%AE%97%5Bx-1%2Fx%26sup2%3B-x-2%5D%C3%B7x%26sup2%3B-2x%2B1%2F2-x%C3%B7%5B1%2Fx%26sup2%3B%2Bx%5D)
[x-1/x²-x-2]÷x²-2x+1/2-x÷[1/x²+x]
=[x-1/(x-2)(x+1)]÷(x-1)^2/2-x*(x+1)x
=(x-1)(2-x)*(x+1)x/(x-2)(x+1)(x-1)^2
=x/1-x
=1/(x-1)-1
=[x-1/(x-2)(x+1)]÷(x-1)^2/2-x*(x+1)x
=(x-1)(2-x)*(x+1)x/(x-2)(x+1)(x-1)^2
=x/1-x
=1/(x-1)-1
2(x²-1²)
计算:[(x²-2x+1)/(x²-1)]÷[(x-1)(x²+x)]-x
x²-1/x²-2x+1÷x+1/x-1 X 1-x/1+x
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