分式求和问题1/(2^k+1)+1/(2^k+2)+…+1/2^(k+1)
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/10 08:58:55
分式求和问题1/(2^k+1)+1/(2^k+2)+…+1/2^(k+1)
为什么1/(2^k+1)+1/(2^k+2)+…+1/2^(k+1)
=1/(2^k+1)+1/(2^k+2)+…+1/[2^k+2^(k-1)]+1/[(2^k+2^(k-1)+1]+1/[(2^k+2^(k-1)+2]+…+1/2^(k+1)
≥2^(k-1)/[2^k+2^(k-1)]+2^(k-1)/2^(k+1)=7/12
如何由第二步到第三步的?
为什么1/(2^k+1)+1/(2^k+2)+…+1/2^(k+1)
=1/(2^k+1)+1/(2^k+2)+…+1/[2^k+2^(k-1)]+1/[(2^k+2^(k-1)+1]+1/[(2^k+2^(k-1)+2]+…+1/2^(k+1)
≥2^(k-1)/[2^k+2^(k-1)]+2^(k-1)/2^(k+1)=7/12
如何由第二步到第三步的?
![分式求和问题1/(2^k+1)+1/(2^k+2)+…+1/2^(k+1)](/uploads/image/z/19959925-13-5.jpg?t=%E5%88%86%E5%BC%8F%E6%B1%82%E5%92%8C%E9%97%AE%E9%A2%981%2F%282%5Ek%2B1%29%2B1%2F%282%5Ek%2B2%29%2B%E2%80%A6%2B1%2F2%5E%28k%2B1%29)
第二步中,前半部分分母全部变为2^k+2^(k-1),后半部分分母全部变为2^(k+1),然后分别相加.
分母增大,则结果变小
分母增大,则结果变小
1k、2k、3k是什么意思
一个级数求和.sigma(k=1,2,3,.) (2^k)/(k!)
[k*(2-4k)/(1+2k)]+2k+1
请问1^k+2^k+3^k+.+n^k=?
3×k×k-2k-1=-1.k等于
1^k+2^k+3^k+.+n^k 有无表达式
K-1+K+2+K/3+K*3=2001
证明(K/K+1)+{1/(K+1)(K+2)}=(K+1)/K+2
K为何值时,分式方程K/(X-2)=k+1/(x-2)无解
为什么月薪叫1K 2K 3K…?
计算2/(k+1)(k+3) +2/(k+3)(k+5)+…+2/(k+2003)(k+2005)
求证:lim1^k+2^k+3^k+4^k+.n^k/n^(k+1)=1/k+1