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(y+2)(y-2)--(y-1)(y+5)

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(y+2)(y-2)--(y-1)(y+5)
123的2次方减去122乘124
(2x +y+z)(2x-y-z)
(x+1)(x+3)-(x-2)的2次方 +(x+2)(x-2)
(a+2b-1)
(-2+ab)(2+ab)
(y+2)(y-2)--(y-1)(y+5)
解(1)(y+2)(y-2)--(y-1)(y+5)
=y²-4 -y²-4y+5 = 1-4y
(2)123的2次方减去122乘124
=123²-(123-1)(123+1) = 123² -123²+1 = 1
(3)2x +y+z)(2x-y-z)
=4x²-(y+z)² = 4x²-y²-z²-2yz
(4)(x+1)(x+3)-(x-2)的2次方 +(x+2)(x-2)
=x²+ 4x +3 -x²+4x-4+x²-4 = x²+8x -5
(5﹚
(6)(-2+ab)(2+ab)
=a²b²- 4