若实数x,y满足x²+y²-10x-2y+26=0,求√x²y²
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若实数x,y满足x²+y²-10x-2y+26=0,求√x²y²
![若实数x,y满足x²+y²-10x-2y+26=0,求√x²y²](/uploads/image/z/19956677-5-7.jpg?t=%E8%8B%A5%E5%AE%9E%E6%95%B0x%2Cy%E6%BB%A1%E8%B6%B3x%26%23178%3B%2By%26%23178%3B-10x-2y%2B26%3D0%2C%E6%B1%82%E2%88%9Ax%26%23178%3By%26%23178%3B)
原式=(x-5)²+(y-1)²=0
所以x=5 y=1
所以 (x²y²)½=5
所以x=5 y=1
所以 (x²y²)½=5
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