若x^2-4xy+5y^2-2y+1=0,求y^x的值.
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若x^2-4xy+5y^2-2y+1=0,求y^x的值.
![若x^2-4xy+5y^2-2y+1=0,求y^x的值.](/uploads/image/z/19954835-35-5.jpg?t=%E8%8B%A5x%5E2-4xy%2B5y%5E2-2y%2B1%3D0%2C%E6%B1%82y%5Ex%E7%9A%84%E5%80%BC.)
x^2-4xy+5y^2-2y+1=0
x^2-4xy+4y^2+y^2-2y+1=0
(x-2y)^2+(y-1)^2=0
(x-2y)^2=0
(y-1)^2=0
y-1=0
y=1
x-2y=0
x=2y=2*1=2
y^x=1^2=1
x^2-4xy+4y^2+y^2-2y+1=0
(x-2y)^2+(y-1)^2=0
(x-2y)^2=0
(y-1)^2=0
y-1=0
y=1
x-2y=0
x=2y=2*1=2
y^x=1^2=1
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