sinx=1/3,sin(x+y)=1,求sin(2x+y)
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sinx=1/3,sin(x+y)=1,求sin(2x+y)
不用考虑角的范围吗
不用考虑角的范围吗
![sinx=1/3,sin(x+y)=1,求sin(2x+y)](/uploads/image/z/19954759-31-9.jpg?t=sinx%3D1%2F3%2Csin%28x%EF%BC%8By%29%3D1%2C%E6%B1%82sin%282x%EF%BC%8By%29)
cosx=±√[1-(sinx)^2]=±2√2/3
cos(x+y)=0
sin(2x+y)=sin[x+(x+y)]
=sinxcos(x+y)+cosxsin(x+y)
=±2√2/3
cos(x+y)=0
sin(2x+y)=sin[x+(x+y)]
=sinxcos(x+y)+cosxsin(x+y)
=±2√2/3
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