(4x-2y-z)-{5x-[8y-2z-(x+y)]-x-
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/08/19 10:28:12
(4x-2y-z)-{5x-[8y-2z-(x+y)]-x-(3y-10z)},其中,x=y=-3,z=-1/2
![(4x-2y-z)-{5x-[8y-2z-(x+y)]-x-](/uploads/image/z/19849938-42-8.jpg?t=%EF%BC%884x-2y-z%29-%7B5x-%5B8y-2z-%28x%2By%29%5D-x-)
解题思路: 根据题意,由整式的运算可求
解题过程:
![](http://img.wesiedu.com/upload/0/b7/0b7f2353210223145c64ac76315fb4f7.jpg)
最终答案:略
解题过程:
![](http://img.wesiedu.com/upload/0/b7/0b7f2353210223145c64ac76315fb4f7.jpg)
最终答案:略
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai
(y-x)/(x+z-2y)(x+y-2z)+(z-y)(x-y)/(x+y-2z)(y+z-2x)+(x-z)(y-z
x,y,z正整数 x>y>z证明 x^2x +y^2y+z^2z>x^(y+z)*y^(x+z)*z^(x+y)
求解2x≥x+y+z 4y≥x+y+Z 8z≥x+y+z x、y、z均大于0
化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+(z-y)(x-y)/(x-2z+y)(y+z-2x)+(x
1.(x+y-z)+(x-y+z)-(x-y-z) 2.2x-(3x-2y+3)-(5y-2)
x+y+z=51 4x+8y+5z=300 x+y+2z=67
(x-2y+z)(x+y-2z)分之(y-x)(z-x) + (x+y-2z)(y+z-2x)分之(z-y)(x-y)
设x、y、z为整数,证明:x^4*(y-z)+y^4*(z-x)+z^4*(x-y)/(y+z)^2+(z+x)^2+(
2X+Y+Z=10,X+2Y+Z=-6,X+Y+2Z=8 5X+4Y-3Y=13,2X-3Y+7Z=19,3X-Y=2X
x/2=y/3=z/5 x+3y-z/x-3y+z
化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+(z-y)(x-y)/(xy-2z)(y+z-2x)+(x-